The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(n^1, INF).

(0) Obligation:

Runtime Complexity TRS:
The TRS R consists of the following rules:

app(x, y) → helpa(0, plus(length(x), length(y)), x, y)
plus(x, 0) → x
plus(x, s(y)) → s(plus(x, y))
length(nil) → 0
length(cons(x, y)) → s(length(y))
helpa(c, l, ys, zs) → if(ge(c, l), c, l, ys, zs)
ge(x, 0) → true
ge(0, s(x)) → false
ge(s(x), s(y)) → ge(x, y)
if(true, c, l, ys, zs) → nil
if(false, c, l, ys, zs) → helpb(c, l, greater(ys, zs), smaller(ys, zs))
greater(ys, zs) → helpc(ge(length(ys), length(zs)), ys, zs)
smaller(ys, zs) → helpc(ge(length(ys), length(zs)), zs, ys)
helpc(true, ys, zs) → ys
helpc(false, ys, zs) → zs
helpb(c, l, cons(y, ys), zs) → cons(y, helpa(s(c), l, ys, zs))

Rewrite Strategy: FULL

(1) RenamingProof (EQUIVALENT transformation)

Renamed function symbols to avoid clashes with predefined symbol.

(2) Obligation:

Runtime Complexity Relative TRS:
The TRS R consists of the following rules:

app(x, y) → helpa(0', plus(length(x), length(y)), x, y)
plus(x, 0') → x
plus(x, s(y)) → s(plus(x, y))
length(nil) → 0'
length(cons(x, y)) → s(length(y))
helpa(c, l, ys, zs) → if(ge(c, l), c, l, ys, zs)
ge(x, 0') → true
ge(0', s(x)) → false
ge(s(x), s(y)) → ge(x, y)
if(true, c, l, ys, zs) → nil
if(false, c, l, ys, zs) → helpb(c, l, greater(ys, zs), smaller(ys, zs))
greater(ys, zs) → helpc(ge(length(ys), length(zs)), ys, zs)
smaller(ys, zs) → helpc(ge(length(ys), length(zs)), zs, ys)
helpc(true, ys, zs) → ys
helpc(false, ys, zs) → zs
helpb(c, l, cons(y, ys), zs) → cons(y, helpa(s(c), l, ys, zs))

S is empty.
Rewrite Strategy: FULL

(3) SlicingProof (LOWER BOUND(ID) transformation)

Sliced the following arguments:
cons/0

(4) Obligation:

Runtime Complexity Relative TRS:
The TRS R consists of the following rules:

app(x, y) → helpa(0', plus(length(x), length(y)), x, y)
plus(x, 0') → x
plus(x, s(y)) → s(plus(x, y))
length(nil) → 0'
length(cons(y)) → s(length(y))
helpa(c, l, ys, zs) → if(ge(c, l), c, l, ys, zs)
ge(x, 0') → true
ge(0', s(x)) → false
ge(s(x), s(y)) → ge(x, y)
if(true, c, l, ys, zs) → nil
if(false, c, l, ys, zs) → helpb(c, l, greater(ys, zs), smaller(ys, zs))
greater(ys, zs) → helpc(ge(length(ys), length(zs)), ys, zs)
smaller(ys, zs) → helpc(ge(length(ys), length(zs)), zs, ys)
helpc(true, ys, zs) → ys
helpc(false, ys, zs) → zs
helpb(c, l, cons(ys), zs) → cons(helpa(s(c), l, ys, zs))

S is empty.
Rewrite Strategy: FULL

(5) TypeInferenceProof (BOTH BOUNDS(ID, ID) transformation)

Infered types.

(6) Obligation:

TRS:
Rules:
app(x, y) → helpa(0', plus(length(x), length(y)), x, y)
plus(x, 0') → x
plus(x, s(y)) → s(plus(x, y))
length(nil) → 0'
length(cons(y)) → s(length(y))
helpa(c, l, ys, zs) → if(ge(c, l), c, l, ys, zs)
ge(x, 0') → true
ge(0', s(x)) → false
ge(s(x), s(y)) → ge(x, y)
if(true, c, l, ys, zs) → nil
if(false, c, l, ys, zs) → helpb(c, l, greater(ys, zs), smaller(ys, zs))
greater(ys, zs) → helpc(ge(length(ys), length(zs)), ys, zs)
smaller(ys, zs) → helpc(ge(length(ys), length(zs)), zs, ys)
helpc(true, ys, zs) → ys
helpc(false, ys, zs) → zs
helpb(c, l, cons(ys), zs) → cons(helpa(s(c), l, ys, zs))

Types:
app :: nil:cons → nil:cons → nil:cons
helpa :: 0':s → 0':s → nil:cons → nil:cons → nil:cons
0' :: 0':s
plus :: 0':s → 0':s → 0':s
length :: nil:cons → 0':s
s :: 0':s → 0':s
nil :: nil:cons
cons :: nil:cons → nil:cons
if :: true:false → 0':s → 0':s → nil:cons → nil:cons → nil:cons
ge :: 0':s → 0':s → true:false
true :: true:false
false :: true:false
helpb :: 0':s → 0':s → nil:cons → nil:cons → nil:cons
greater :: nil:cons → nil:cons → nil:cons
smaller :: nil:cons → nil:cons → nil:cons
helpc :: true:false → nil:cons → nil:cons → nil:cons
hole_nil:cons1_0 :: nil:cons
hole_0':s2_0 :: 0':s
hole_true:false3_0 :: true:false
gen_nil:cons4_0 :: Nat → nil:cons
gen_0':s5_0 :: Nat → 0':s

(7) OrderProof (LOWER BOUND(ID) transformation)

Heuristically decided to analyse the following defined symbols:
helpa, plus, length, ge, helpb

They will be analysed ascendingly in the following order:
ge < helpa
helpa = helpb

(8) Obligation:

TRS:
Rules:
app(x, y) → helpa(0', plus(length(x), length(y)), x, y)
plus(x, 0') → x
plus(x, s(y)) → s(plus(x, y))
length(nil) → 0'
length(cons(y)) → s(length(y))
helpa(c, l, ys, zs) → if(ge(c, l), c, l, ys, zs)
ge(x, 0') → true
ge(0', s(x)) → false
ge(s(x), s(y)) → ge(x, y)
if(true, c, l, ys, zs) → nil
if(false, c, l, ys, zs) → helpb(c, l, greater(ys, zs), smaller(ys, zs))
greater(ys, zs) → helpc(ge(length(ys), length(zs)), ys, zs)
smaller(ys, zs) → helpc(ge(length(ys), length(zs)), zs, ys)
helpc(true, ys, zs) → ys
helpc(false, ys, zs) → zs
helpb(c, l, cons(ys), zs) → cons(helpa(s(c), l, ys, zs))

Types:
app :: nil:cons → nil:cons → nil:cons
helpa :: 0':s → 0':s → nil:cons → nil:cons → nil:cons
0' :: 0':s
plus :: 0':s → 0':s → 0':s
length :: nil:cons → 0':s
s :: 0':s → 0':s
nil :: nil:cons
cons :: nil:cons → nil:cons
if :: true:false → 0':s → 0':s → nil:cons → nil:cons → nil:cons
ge :: 0':s → 0':s → true:false
true :: true:false
false :: true:false
helpb :: 0':s → 0':s → nil:cons → nil:cons → nil:cons
greater :: nil:cons → nil:cons → nil:cons
smaller :: nil:cons → nil:cons → nil:cons
helpc :: true:false → nil:cons → nil:cons → nil:cons
hole_nil:cons1_0 :: nil:cons
hole_0':s2_0 :: 0':s
hole_true:false3_0 :: true:false
gen_nil:cons4_0 :: Nat → nil:cons
gen_0':s5_0 :: Nat → 0':s

Generator Equations:
gen_nil:cons4_0(0) ⇔ nil
gen_nil:cons4_0(+(x, 1)) ⇔ cons(gen_nil:cons4_0(x))
gen_0':s5_0(0) ⇔ 0'
gen_0':s5_0(+(x, 1)) ⇔ s(gen_0':s5_0(x))

The following defined symbols remain to be analysed:
plus, helpa, length, ge, helpb

They will be analysed ascendingly in the following order:
ge < helpa
helpa = helpb

(9) RewriteLemmaProof (LOWER BOUND(ID) transformation)

Proved the following rewrite lemma:
plus(gen_0':s5_0(a), gen_0':s5_0(n7_0)) → gen_0':s5_0(+(n7_0, a)), rt ∈ Ω(1 + n7₀)

Induction Base:
plus(gen_0':s5_0(a), gen_0':s5_0(0)) →_R^Ω(1)
gen_0':s5_0(a)

Induction Step:
plus(gen_0':s5_0(a), gen_0':s5_0(+(n7_0, 1))) →_R^Ω(1)
s(plus(gen_0':s5_0(a), gen_0':s5_0(n7_0))) →_IH
s(gen_0':s5_0(+(a, c8_0)))

We have rt ∈ Ω(n¹) and sz ∈ O(n). Thus, we have irc_R ∈ Ω(n).

(10) Complex Obligation (BEST)

(11) Obligation:

TRS:
Rules:
app(x, y) → helpa(0', plus(length(x), length(y)), x, y)
plus(x, 0') → x
plus(x, s(y)) → s(plus(x, y))
length(nil) → 0'
length(cons(y)) → s(length(y))
helpa(c, l, ys, zs) → if(ge(c, l), c, l, ys, zs)
ge(x, 0') → true
ge(0', s(x)) → false
ge(s(x), s(y)) → ge(x, y)
if(true, c, l, ys, zs) → nil
if(false, c, l, ys, zs) → helpb(c, l, greater(ys, zs), smaller(ys, zs))
greater(ys, zs) → helpc(ge(length(ys), length(zs)), ys, zs)
smaller(ys, zs) → helpc(ge(length(ys), length(zs)), zs, ys)
helpc(true, ys, zs) → ys
helpc(false, ys, zs) → zs
helpb(c, l, cons(ys), zs) → cons(helpa(s(c), l, ys, zs))

Types:
app :: nil:cons → nil:cons → nil:cons
helpa :: 0':s → 0':s → nil:cons → nil:cons → nil:cons
0' :: 0':s
plus :: 0':s → 0':s → 0':s
length :: nil:cons → 0':s
s :: 0':s → 0':s
nil :: nil:cons
cons :: nil:cons → nil:cons
if :: true:false → 0':s → 0':s → nil:cons → nil:cons → nil:cons
ge :: 0':s → 0':s → true:false
true :: true:false
false :: true:false
helpb :: 0':s → 0':s → nil:cons → nil:cons → nil:cons
greater :: nil:cons → nil:cons → nil:cons
smaller :: nil:cons → nil:cons → nil:cons
helpc :: true:false → nil:cons → nil:cons → nil:cons
hole_nil:cons1_0 :: nil:cons
hole_0':s2_0 :: 0':s
hole_true:false3_0 :: true:false
gen_nil:cons4_0 :: Nat → nil:cons
gen_0':s5_0 :: Nat → 0':s

Lemmas:
plus(gen_0':s5_0(a), gen_0':s5_0(n7_0)) → gen_0':s5_0(+(n7_0, a)), rt ∈ Ω(1 + n7₀)

Generator Equations:
gen_nil:cons4_0(0) ⇔ nil
gen_nil:cons4_0(+(x, 1)) ⇔ cons(gen_nil:cons4_0(x))
gen_0':s5_0(0) ⇔ 0'
gen_0':s5_0(+(x, 1)) ⇔ s(gen_0':s5_0(x))

The following defined symbols remain to be analysed:
length, helpa, ge, helpb

They will be analysed ascendingly in the following order:
ge < helpa
helpa = helpb

(12) RewriteLemmaProof (LOWER BOUND(ID) transformation)

Proved the following rewrite lemma:
length(gen_nil:cons4_0(n824_0)) → gen_0':s5_0(n824_0), rt ∈ Ω(1 + n824₀)

Induction Base:
length(gen_nil:cons4_0(0)) →_R^Ω(1)
0'

Induction Step:
length(gen_nil:cons4_0(+(n824_0, 1))) →_R^Ω(1)
s(length(gen_nil:cons4_0(n824_0))) →_IH
s(gen_0':s5_0(c825_0))

We have rt ∈ Ω(n¹) and sz ∈ O(n). Thus, we have irc_R ∈ Ω(n).

(13) Complex Obligation (BEST)

(14) Obligation:

TRS:
Rules:
app(x, y) → helpa(0', plus(length(x), length(y)), x, y)
plus(x, 0') → x
plus(x, s(y)) → s(plus(x, y))
length(nil) → 0'
length(cons(y)) → s(length(y))
helpa(c, l, ys, zs) → if(ge(c, l), c, l, ys, zs)
ge(x, 0') → true
ge(0', s(x)) → false
ge(s(x), s(y)) → ge(x, y)
if(true, c, l, ys, zs) → nil
if(false, c, l, ys, zs) → helpb(c, l, greater(ys, zs), smaller(ys, zs))
greater(ys, zs) → helpc(ge(length(ys), length(zs)), ys, zs)
smaller(ys, zs) → helpc(ge(length(ys), length(zs)), zs, ys)
helpc(true, ys, zs) → ys
helpc(false, ys, zs) → zs
helpb(c, l, cons(ys), zs) → cons(helpa(s(c), l, ys, zs))

Types:
app :: nil:cons → nil:cons → nil:cons
helpa :: 0':s → 0':s → nil:cons → nil:cons → nil:cons
0' :: 0':s
plus :: 0':s → 0':s → 0':s
length :: nil:cons → 0':s
s :: 0':s → 0':s
nil :: nil:cons
cons :: nil:cons → nil:cons
if :: true:false → 0':s → 0':s → nil:cons → nil:cons → nil:cons
ge :: 0':s → 0':s → true:false
true :: true:false
false :: true:false
helpb :: 0':s → 0':s → nil:cons → nil:cons → nil:cons
greater :: nil:cons → nil:cons → nil:cons
smaller :: nil:cons → nil:cons → nil:cons
helpc :: true:false → nil:cons → nil:cons → nil:cons
hole_nil:cons1_0 :: nil:cons
hole_0':s2_0 :: 0':s
hole_true:false3_0 :: true:false
gen_nil:cons4_0 :: Nat → nil:cons
gen_0':s5_0 :: Nat → 0':s

Lemmas:
plus(gen_0':s5_0(a), gen_0':s5_0(n7_0)) → gen_0':s5_0(+(n7_0, a)), rt ∈ Ω(1 + n7₀)
length(gen_nil:cons4_0(n824_0)) → gen_0':s5_0(n824_0), rt ∈ Ω(1 + n824₀)

Generator Equations:
gen_nil:cons4_0(0) ⇔ nil
gen_nil:cons4_0(+(x, 1)) ⇔ cons(gen_nil:cons4_0(x))
gen_0':s5_0(0) ⇔ 0'
gen_0':s5_0(+(x, 1)) ⇔ s(gen_0':s5_0(x))

The following defined symbols remain to be analysed:
ge, helpa, helpb

They will be analysed ascendingly in the following order:
ge < helpa
helpa = helpb

(15) RewriteLemmaProof (LOWER BOUND(ID) transformation)

Proved the following rewrite lemma:
ge(gen_0':s5_0(n1080_0), gen_0':s5_0(n1080_0)) → true, rt ∈ Ω(1 + n1080₀)

Induction Base:
ge(gen_0':s5_0(0), gen_0':s5_0(0)) →_R^Ω(1)
true

Induction Step:
ge(gen_0':s5_0(+(n1080_0, 1)), gen_0':s5_0(+(n1080_0, 1))) →_R^Ω(1)
ge(gen_0':s5_0(n1080_0), gen_0':s5_0(n1080_0)) →_IH
true

We have rt ∈ Ω(n¹) and sz ∈ O(n). Thus, we have irc_R ∈ Ω(n).

(16) Complex Obligation (BEST)

(17) Obligation:

TRS:
Rules:
app(x, y) → helpa(0', plus(length(x), length(y)), x, y)
plus(x, 0') → x
plus(x, s(y)) → s(plus(x, y))
length(nil) → 0'
length(cons(y)) → s(length(y))
helpa(c, l, ys, zs) → if(ge(c, l), c, l, ys, zs)
ge(x, 0') → true
ge(0', s(x)) → false
ge(s(x), s(y)) → ge(x, y)
if(true, c, l, ys, zs) → nil
if(false, c, l, ys, zs) → helpb(c, l, greater(ys, zs), smaller(ys, zs))
greater(ys, zs) → helpc(ge(length(ys), length(zs)), ys, zs)
smaller(ys, zs) → helpc(ge(length(ys), length(zs)), zs, ys)
helpc(true, ys, zs) → ys
helpc(false, ys, zs) → zs
helpb(c, l, cons(ys), zs) → cons(helpa(s(c), l, ys, zs))

Types:
app :: nil:cons → nil:cons → nil:cons
helpa :: 0':s → 0':s → nil:cons → nil:cons → nil:cons
0' :: 0':s
plus :: 0':s → 0':s → 0':s
length :: nil:cons → 0':s
s :: 0':s → 0':s
nil :: nil:cons
cons :: nil:cons → nil:cons
if :: true:false → 0':s → 0':s → nil:cons → nil:cons → nil:cons
ge :: 0':s → 0':s → true:false
true :: true:false
false :: true:false
helpb :: 0':s → 0':s → nil:cons → nil:cons → nil:cons
greater :: nil:cons → nil:cons → nil:cons
smaller :: nil:cons → nil:cons → nil:cons
helpc :: true:false → nil:cons → nil:cons → nil:cons
hole_nil:cons1_0 :: nil:cons
hole_0':s2_0 :: 0':s
hole_true:false3_0 :: true:false
gen_nil:cons4_0 :: Nat → nil:cons
gen_0':s5_0 :: Nat → 0':s

Lemmas:
plus(gen_0':s5_0(a), gen_0':s5_0(n7_0)) → gen_0':s5_0(+(n7_0, a)), rt ∈ Ω(1 + n7₀)
length(gen_nil:cons4_0(n824_0)) → gen_0':s5_0(n824_0), rt ∈ Ω(1 + n824₀)
ge(gen_0':s5_0(n1080_0), gen_0':s5_0(n1080_0)) → true, rt ∈ Ω(1 + n1080₀)

Generator Equations:
gen_nil:cons4_0(0) ⇔ nil
gen_nil:cons4_0(+(x, 1)) ⇔ cons(gen_nil:cons4_0(x))
gen_0':s5_0(0) ⇔ 0'
gen_0':s5_0(+(x, 1)) ⇔ s(gen_0':s5_0(x))

The following defined symbols remain to be analysed:
helpb, helpa

They will be analysed ascendingly in the following order:
helpa = helpb

(18) NoRewriteLemmaProof (LOWER BOUND(ID) transformation)

Could not prove a rewrite lemma for the defined symbol helpb.

(19) Obligation:

TRS:
Rules:
app(x, y) → helpa(0', plus(length(x), length(y)), x, y)
plus(x, 0') → x
plus(x, s(y)) → s(plus(x, y))
length(nil) → 0'
length(cons(y)) → s(length(y))
helpa(c, l, ys, zs) → if(ge(c, l), c, l, ys, zs)
ge(x, 0') → true
ge(0', s(x)) → false
ge(s(x), s(y)) → ge(x, y)
if(true, c, l, ys, zs) → nil
if(false, c, l, ys, zs) → helpb(c, l, greater(ys, zs), smaller(ys, zs))
greater(ys, zs) → helpc(ge(length(ys), length(zs)), ys, zs)
smaller(ys, zs) → helpc(ge(length(ys), length(zs)), zs, ys)
helpc(true, ys, zs) → ys
helpc(false, ys, zs) → zs
helpb(c, l, cons(ys), zs) → cons(helpa(s(c), l, ys, zs))

Types:
app :: nil:cons → nil:cons → nil:cons
helpa :: 0':s → 0':s → nil:cons → nil:cons → nil:cons
0' :: 0':s
plus :: 0':s → 0':s → 0':s
length :: nil:cons → 0':s
s :: 0':s → 0':s
nil :: nil:cons
cons :: nil:cons → nil:cons
if :: true:false → 0':s → 0':s → nil:cons → nil:cons → nil:cons
ge :: 0':s → 0':s → true:false
true :: true:false
false :: true:false
helpb :: 0':s → 0':s → nil:cons → nil:cons → nil:cons
greater :: nil:cons → nil:cons → nil:cons
smaller :: nil:cons → nil:cons → nil:cons
helpc :: true:false → nil:cons → nil:cons → nil:cons
hole_nil:cons1_0 :: nil:cons
hole_0':s2_0 :: 0':s
hole_true:false3_0 :: true:false
gen_nil:cons4_0 :: Nat → nil:cons
gen_0':s5_0 :: Nat → 0':s

Lemmas:
plus(gen_0':s5_0(a), gen_0':s5_0(n7_0)) → gen_0':s5_0(+(n7_0, a)), rt ∈ Ω(1 + n7₀)
length(gen_nil:cons4_0(n824_0)) → gen_0':s5_0(n824_0), rt ∈ Ω(1 + n824₀)
ge(gen_0':s5_0(n1080_0), gen_0':s5_0(n1080_0)) → true, rt ∈ Ω(1 + n1080₀)

Generator Equations:
gen_nil:cons4_0(0) ⇔ nil
gen_nil:cons4_0(+(x, 1)) ⇔ cons(gen_nil:cons4_0(x))
gen_0':s5_0(0) ⇔ 0'
gen_0':s5_0(+(x, 1)) ⇔ s(gen_0':s5_0(x))

The following defined symbols remain to be analysed:
helpa

They will be analysed ascendingly in the following order:
helpa = helpb

(20) NoRewriteLemmaProof (LOWER BOUND(ID) transformation)

Could not prove a rewrite lemma for the defined symbol helpa.

(21) Obligation:

TRS:
Rules:
app(x, y) → helpa(0', plus(length(x), length(y)), x, y)
plus(x, 0') → x
plus(x, s(y)) → s(plus(x, y))
length(nil) → 0'
length(cons(y)) → s(length(y))
helpa(c, l, ys, zs) → if(ge(c, l), c, l, ys, zs)
ge(x, 0') → true
ge(0', s(x)) → false
ge(s(x), s(y)) → ge(x, y)
if(true, c, l, ys, zs) → nil
if(false, c, l, ys, zs) → helpb(c, l, greater(ys, zs), smaller(ys, zs))
greater(ys, zs) → helpc(ge(length(ys), length(zs)), ys, zs)
smaller(ys, zs) → helpc(ge(length(ys), length(zs)), zs, ys)
helpc(true, ys, zs) → ys
helpc(false, ys, zs) → zs
helpb(c, l, cons(ys), zs) → cons(helpa(s(c), l, ys, zs))

Types:
app :: nil:cons → nil:cons → nil:cons
helpa :: 0':s → 0':s → nil:cons → nil:cons → nil:cons
0' :: 0':s
plus :: 0':s → 0':s → 0':s
length :: nil:cons → 0':s
s :: 0':s → 0':s
nil :: nil:cons
cons :: nil:cons → nil:cons
if :: true:false → 0':s → 0':s → nil:cons → nil:cons → nil:cons
ge :: 0':s → 0':s → true:false
true :: true:false
false :: true:false
helpb :: 0':s → 0':s → nil:cons → nil:cons → nil:cons
greater :: nil:cons → nil:cons → nil:cons
smaller :: nil:cons → nil:cons → nil:cons
helpc :: true:false → nil:cons → nil:cons → nil:cons
hole_nil:cons1_0 :: nil:cons
hole_0':s2_0 :: 0':s
hole_true:false3_0 :: true:false
gen_nil:cons4_0 :: Nat → nil:cons
gen_0':s5_0 :: Nat → 0':s

Lemmas:
plus(gen_0':s5_0(a), gen_0':s5_0(n7_0)) → gen_0':s5_0(+(n7_0, a)), rt ∈ Ω(1 + n7₀)
length(gen_nil:cons4_0(n824_0)) → gen_0':s5_0(n824_0), rt ∈ Ω(1 + n824₀)
ge(gen_0':s5_0(n1080_0), gen_0':s5_0(n1080_0)) → true, rt ∈ Ω(1 + n1080₀)

Generator Equations:
gen_nil:cons4_0(0) ⇔ nil
gen_nil:cons4_0(+(x, 1)) ⇔ cons(gen_nil:cons4_0(x))
gen_0':s5_0(0) ⇔ 0'
gen_0':s5_0(+(x, 1)) ⇔ s(gen_0':s5_0(x))

No more defined symbols left to analyse.

(22) LowerBoundsProof (EQUIVALENT transformation)

The lowerbound Ω(n¹) was proven with the following lemma:
plus(gen_0':s5_0(a), gen_0':s5_0(n7_0)) → gen_0':s5_0(+(n7_0, a)), rt ∈ Ω(1 + n7₀)

(23) BOUNDS(n^1, INF)

(24) Obligation:

TRS:
Rules:
app(x, y) → helpa(0', plus(length(x), length(y)), x, y)
plus(x, 0') → x
plus(x, s(y)) → s(plus(x, y))
length(nil) → 0'
length(cons(y)) → s(length(y))
helpa(c, l, ys, zs) → if(ge(c, l), c, l, ys, zs)
ge(x, 0') → true
ge(0', s(x)) → false
ge(s(x), s(y)) → ge(x, y)
if(true, c, l, ys, zs) → nil
if(false, c, l, ys, zs) → helpb(c, l, greater(ys, zs), smaller(ys, zs))
greater(ys, zs) → helpc(ge(length(ys), length(zs)), ys, zs)
smaller(ys, zs) → helpc(ge(length(ys), length(zs)), zs, ys)
helpc(true, ys, zs) → ys
helpc(false, ys, zs) → zs
helpb(c, l, cons(ys), zs) → cons(helpa(s(c), l, ys, zs))

Types:
app :: nil:cons → nil:cons → nil:cons
helpa :: 0':s → 0':s → nil:cons → nil:cons → nil:cons
0' :: 0':s
plus :: 0':s → 0':s → 0':s
length :: nil:cons → 0':s
s :: 0':s → 0':s
nil :: nil:cons
cons :: nil:cons → nil:cons
if :: true:false → 0':s → 0':s → nil:cons → nil:cons → nil:cons
ge :: 0':s → 0':s → true:false
true :: true:false
false :: true:false
helpb :: 0':s → 0':s → nil:cons → nil:cons → nil:cons
greater :: nil:cons → nil:cons → nil:cons
smaller :: nil:cons → nil:cons → nil:cons
helpc :: true:false → nil:cons → nil:cons → nil:cons
hole_nil:cons1_0 :: nil:cons
hole_0':s2_0 :: 0':s
hole_true:false3_0 :: true:false
gen_nil:cons4_0 :: Nat → nil:cons
gen_0':s5_0 :: Nat → 0':s

Lemmas:
plus(gen_0':s5_0(a), gen_0':s5_0(n7_0)) → gen_0':s5_0(+(n7_0, a)), rt ∈ Ω(1 + n7₀)
length(gen_nil:cons4_0(n824_0)) → gen_0':s5_0(n824_0), rt ∈ Ω(1 + n824₀)
ge(gen_0':s5_0(n1080_0), gen_0':s5_0(n1080_0)) → true, rt ∈ Ω(1 + n1080₀)

Generator Equations:
gen_nil:cons4_0(0) ⇔ nil
gen_nil:cons4_0(+(x, 1)) ⇔ cons(gen_nil:cons4_0(x))
gen_0':s5_0(0) ⇔ 0'
gen_0':s5_0(+(x, 1)) ⇔ s(gen_0':s5_0(x))

No more defined symbols left to analyse.

(25) LowerBoundsProof (EQUIVALENT transformation)

The lowerbound Ω(n¹) was proven with the following lemma:
plus(gen_0':s5_0(a), gen_0':s5_0(n7_0)) → gen_0':s5_0(+(n7_0, a)), rt ∈ Ω(1 + n7₀)

(26) BOUNDS(n^1, INF)

(27) Obligation:

TRS:
Rules:
app(x, y) → helpa(0', plus(length(x), length(y)), x, y)
plus(x, 0') → x
plus(x, s(y)) → s(plus(x, y))
length(nil) → 0'
length(cons(y)) → s(length(y))
helpa(c, l, ys, zs) → if(ge(c, l), c, l, ys, zs)
ge(x, 0') → true
ge(0', s(x)) → false
ge(s(x), s(y)) → ge(x, y)
if(true, c, l, ys, zs) → nil
if(false, c, l, ys, zs) → helpb(c, l, greater(ys, zs), smaller(ys, zs))
greater(ys, zs) → helpc(ge(length(ys), length(zs)), ys, zs)
smaller(ys, zs) → helpc(ge(length(ys), length(zs)), zs, ys)
helpc(true, ys, zs) → ys
helpc(false, ys, zs) → zs
helpb(c, l, cons(ys), zs) → cons(helpa(s(c), l, ys, zs))

Types:
app :: nil:cons → nil:cons → nil:cons
helpa :: 0':s → 0':s → nil:cons → nil:cons → nil:cons
0' :: 0':s
plus :: 0':s → 0':s → 0':s
length :: nil:cons → 0':s
s :: 0':s → 0':s
nil :: nil:cons
cons :: nil:cons → nil:cons
if :: true:false → 0':s → 0':s → nil:cons → nil:cons → nil:cons
ge :: 0':s → 0':s → true:false
true :: true:false
false :: true:false
helpb :: 0':s → 0':s → nil:cons → nil:cons → nil:cons
greater :: nil:cons → nil:cons → nil:cons
smaller :: nil:cons → nil:cons → nil:cons
helpc :: true:false → nil:cons → nil:cons → nil:cons
hole_nil:cons1_0 :: nil:cons
hole_0':s2_0 :: 0':s
hole_true:false3_0 :: true:false
gen_nil:cons4_0 :: Nat → nil:cons
gen_0':s5_0 :: Nat → 0':s

Lemmas:
plus(gen_0':s5_0(a), gen_0':s5_0(n7_0)) → gen_0':s5_0(+(n7_0, a)), rt ∈ Ω(1 + n7₀)
length(gen_nil:cons4_0(n824_0)) → gen_0':s5_0(n824_0), rt ∈ Ω(1 + n824₀)

Generator Equations:
gen_nil:cons4_0(0) ⇔ nil
gen_nil:cons4_0(+(x, 1)) ⇔ cons(gen_nil:cons4_0(x))
gen_0':s5_0(0) ⇔ 0'
gen_0':s5_0(+(x, 1)) ⇔ s(gen_0':s5_0(x))

No more defined symbols left to analyse.

(28) LowerBoundsProof (EQUIVALENT transformation)

The lowerbound Ω(n¹) was proven with the following lemma:
plus(gen_0':s5_0(a), gen_0':s5_0(n7_0)) → gen_0':s5_0(+(n7_0, a)), rt ∈ Ω(1 + n7₀)

(29) BOUNDS(n^1, INF)

(30) Obligation:

TRS:
Rules:
app(x, y) → helpa(0', plus(length(x), length(y)), x, y)
plus(x, 0') → x
plus(x, s(y)) → s(plus(x, y))
length(nil) → 0'
length(cons(y)) → s(length(y))
helpa(c, l, ys, zs) → if(ge(c, l), c, l, ys, zs)
ge(x, 0') → true
ge(0', s(x)) → false
ge(s(x), s(y)) → ge(x, y)
if(true, c, l, ys, zs) → nil
if(false, c, l, ys, zs) → helpb(c, l, greater(ys, zs), smaller(ys, zs))
greater(ys, zs) → helpc(ge(length(ys), length(zs)), ys, zs)
smaller(ys, zs) → helpc(ge(length(ys), length(zs)), zs, ys)
helpc(true, ys, zs) → ys
helpc(false, ys, zs) → zs
helpb(c, l, cons(ys), zs) → cons(helpa(s(c), l, ys, zs))

Types:
app :: nil:cons → nil:cons → nil:cons
helpa :: 0':s → 0':s → nil:cons → nil:cons → nil:cons
0' :: 0':s
plus :: 0':s → 0':s → 0':s
length :: nil:cons → 0':s
s :: 0':s → 0':s
nil :: nil:cons
cons :: nil:cons → nil:cons
if :: true:false → 0':s → 0':s → nil:cons → nil:cons → nil:cons
ge :: 0':s → 0':s → true:false
true :: true:false
false :: true:false
helpb :: 0':s → 0':s → nil:cons → nil:cons → nil:cons
greater :: nil:cons → nil:cons → nil:cons
smaller :: nil:cons → nil:cons → nil:cons
helpc :: true:false → nil:cons → nil:cons → nil:cons
hole_nil:cons1_0 :: nil:cons
hole_0':s2_0 :: 0':s
hole_true:false3_0 :: true:false
gen_nil:cons4_0 :: Nat → nil:cons
gen_0':s5_0 :: Nat → 0':s

Lemmas:
plus(gen_0':s5_0(a), gen_0':s5_0(n7_0)) → gen_0':s5_0(+(n7_0, a)), rt ∈ Ω(1 + n7₀)

Generator Equations:
gen_nil:cons4_0(0) ⇔ nil
gen_nil:cons4_0(+(x, 1)) ⇔ cons(gen_nil:cons4_0(x))
gen_0':s5_0(0) ⇔ 0'
gen_0':s5_0(+(x, 1)) ⇔ s(gen_0':s5_0(x))

No more defined symbols left to analyse.

(31) LowerBoundsProof (EQUIVALENT transformation)

The lowerbound Ω(n¹) was proven with the following lemma:
plus(gen_0':s5_0(a), gen_0':s5_0(n7_0)) → gen_0':s5_0(+(n7_0, a)), rt ∈ Ω(1 + n7₀)

(32) BOUNDS(n^1, INF)